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Show that for a first order reaction half life is independent of initial concentration. - Chemistry (Theory)

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प्रश्न

Show that for a first order reaction half life is independent of initial concentration.

Show that half-life period does not depend upon the initial concentration for the first order reaction.

संख्यात्मक
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उत्तर

For a first order reaction, the half-life is a constant, i.e., it does not depend on the initial concentration.

The rate constant for a first order reaction is given by,

k = `2.303/t log  ([A_0])/([A])`

at t = `t_(1//2)`; [A] = `([A_0])/2`

k = `2.303/t_(1//2) log  ([A_0])/(([A_0])/2)`

k = `2.303/t_(1//2) log (2)`

k = `(2.303 xx 0.3010)/t_(1//2)`

k = `0.693/t_(1//2)`

`t_(1//2) = 0.693/k`

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पाठ 7: Chemical Kinetics - Evaluation [पृष्ठ २३०]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
पाठ 7 Chemical Kinetics
Evaluation | Q 4. | पृष्ठ २३०

संबंधित प्रश्‍न

The integrated rate equation for first order reaction is A → products


Derive the relation between half life and rate constant for a first order reaction


The rate constant for a first order reaction is 100 s–1. The time required for completion of 50% of reaction is _______.

(A) 0.0693 milliseconds

(B) 0.693 milliseconds

(C) 6.93 milliseconds

(D) 69.3 milliseconds


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(log 2 = 0.3010)


The experimental data for decomposition of N2O5.

\[\ce{2N2O5 -> 4NO2 + O2}\] in gas phase at 318 K are given below:

t/s 0 400 800 1200 1600 2000 2400 2800 3200
102 × [N2O5]/mol L−1 1.63 1.36 1.14 0.93 0.78 0.64 0.53 0.43 0.35
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  2. Find the half-life period for the reaction.
  3. Draw a graph between log [N2O5] and t.
  4. What is the rate law?
  5. Calculate the rate constant.
  6. Calculate the half-life period from k and compare it with (ii).

Show that the time required for 99% completion is double of the time required for the completion of 90% reaction.


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(Round off to the nearest integer).
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