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प्रश्न
Draw a cumulative frequency curve (ogive) for the following distributions:
| Class Interval | 10 – 19 | 20 – 29 | 30 – 39 | 40 – 49 | 50 – 59 |
| Frequency | 23 | 16 | 15 | 20 | 12 |
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उत्तर
The above distribution is discontinuous converting into continuous distribution, we get:
Adjustment factor = `("Lower limit of one class" - "Upper limit of previous class") / 2`
= `(20 - 19)/2`
= `1/2`
= 0.5
Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.
| Class Interval (Inclusive) | Class Interval (Exclusive) | Frequency | Cumulative Frequency |
| 10 – 19 | 9.5 – 19.5 | 23 | 23 |
| 20 – 29 | 19.5 – 29.5 | 16 | 39 |
| 30 – 39 | 29.5 – 39.5 | 15 | 54 |
| 40 – 49 | 39.5 – 49.5 | 20 | 74 |
| 50 – 59 | 49.5 – 59.5 | 12 | 86 |
| Total | 86 |
Steps of construction of ogive:
- Since, the scale on x-axis starts at 9.5, a break (kink) is shown near the origin on x-axis to indicate that the graph is drawn to scale beginning at 9.5.
- Take 2 cm = 10 units along the x-axis.
- Take 1 cm = 10 units along the y-axis.
- Ogive always starts from a point on the x-axis, representing the lower limit of the first class. Mark point (9.5, 0).
- Take upper-class limits along the x-axis and corresponding cumulative frequencies along the y-axis, and mark the points (19.5, 23), (29.5, 39), (39.5, 54), (49.5, 74) and (59.5, 86).
- Join the points marked by a free-hand curve.
The required ogive is shown in the below figure:

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