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प्रश्न
Distinguish between:
High Earth orbit - Medium Earth orbit.
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उत्तर
| High earth orbits | Medium earth orbits | |
| 1. | Height from the earth’s surface for these orbits is greater than or equal to 35780 km. | Height from the earth’s surface for these orbits is between 2000 km and 35780 km. |
| 2. | Satellites revolving in these orbits take around 24 hours to complete one revolution around the earth. | Satellites revolving in these orbits take around 2 to 24 hours to complete one revolution around the earth. |
| 3. | The satellites revolving in these orbits appear stationary with respect to earth. | The satellites revolving in these orbits do not appear stationary with respect to earth. |
| 4. | Satellites revolving in these orbits can be used for carrying signals for telephone, television etc. and also in the applications like meteorology. | Satellites revolving in these orbits can be used in the study of polar regions. |
| 5. | Example: IBEX (Interstellar Boundary Explorer) revolves in this orbit. | Examples: GLONASS (Global Navigation Satellite System) and Telstar – 1 revolve in these orbits. |
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संबंधित प्रश्न
Fill in the blank and explain the statement with reasoning:
If the height of the orbit of a satellite from the earth surface is increased, the tangential velocity of the satellite will ......
Why are geostationary satellites not useful for studies of polar regions?
Complete the following table.
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2
Name the first artificial satellite sent by Russia in space.
The function of a satellite launcher is based on Newton's second law of motion.
Note the relationship between the entries in all the three columns in the table and rewrite the table.
| Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
| Earth’s surface (average) | 8.8 | 0.225 |
| Mount Everest | 36.6 | 9.81 |
| The highest height ever reached by man made balloon | 400 | 9.8 |
| Orbit of spacecraft | 35700 | 9.77 |
| Orbit of communication satellite | 0 | 8.7 |
Why are some satellites called geostationary?
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
The orbital velocity of the satellite depends on its ______.
Give scientific reasons.
The geostationary satellite is not useful in the study of polar regions.
Geostationary satellites are not useful for studies of the polar region.
Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
Complete the Following table.
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: ______ |
| Launcher: ______ | ||
| (2) | Earth Observation Satellite | Satellite: ______ |
| Launcher: ______ |
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
