Advertisements
Advertisements
प्रश्न
Determine whether the following function is odd or even?
f(x) = x2 – |x|
बेरीज
Advertisements
उत्तर
Given f(x) = x2 – |x|
f(-x) = (-x)2 – |-x|
= x2 – |x|
= f(x)
∴ f(x) is an even function.
shaalaa.com
Functions and Their Graphs
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Differential Calculus - Exercise 5.1 [पृष्ठ १०५]
APPEARS IN
संबंधित प्रश्न
Let f be defined by f(x) = x3 – kx2 + 2x, x ∈ R. Find k, if ‘f’ is an odd function.
If f(x) = `((x + 1)/(x - 1))`, then prove that f(f(x)) = x.
For f(x) = `(x - 1)/(3x + 1)`, write the expressions of `"f"(1/x) and 1/("f"(x))`
If f(x) = ex and g(x) = loge x then find (f + g)(1)
If f(x) = ex and g(x) = loge x then find (fg)(1).
Draw the graph of the following function:
f(x) = |x – 2|
If f(x) = `{(x^2 - 4x if x >= 2),(x+2 if x < 2):}`, then f(5) is
If f(x) = `(1 - x)/(1 + x)` then f(-x) is equal to:
The minimum value of the function f(x) = |x| is:
If f(x) = 2x and g(x) = `1/2^x` then (fg)(x) is:
