Advertisements
Advertisements
प्रश्न
Determine whether the following function is odd or even?
f(x) = x2 – |x|
योग
Advertisements
उत्तर
Given f(x) = x2 – |x|
f(-x) = (-x)2 – |-x|
= x2 – |x|
= f(x)
∴ f(x) is an even function.
shaalaa.com
Functions and Their Graphs
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Differential Calculus - Exercise 5.1 [पृष्ठ १०५]
APPEARS IN
संबंधित प्रश्न
If f(x) = `x^3 - 1/x^3`, then show that `"f"(x) + "f"(1/x)` = 0
For f(x) = `(x - 1)/(3x + 1)`, write the expressions of `"f"(1/x) and 1/("f"(x))`
If f(x) = ex and g(x) = loge x then find (fg)(1).
Draw the graph of the following function:
f(x) = e2x
Draw the graph of the following function:
f(x) = e-2x
If f(x) = `(1 - x)/(1 + x)` then f(-x) is equal to:
The graph of the line y = 3 is
If f(x) = 2x and g(x) = `1/2^x` then (fg)(x) is:
The range of f(x) = |x|, for all x ∈ R is:
The graph of f(x) = ex is identical to that of:
