Advertisements
Advertisements
प्रश्न
Determine whether the following function is odd or even?
f(x) = x + x2
बेरीज
Advertisements
उत्तर
f(x) = x + x2
f(-x) = (-x) + (-x)2 = -x + x2
Since f(-x) ≠ f(x), f(-x) ≠ -f(x).
∴ f(x) is neither odd nor even function.
shaalaa.com
Functions and Their Graphs
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Determine whether the following function is odd or even?
f(x) = x2 – |x|
If f(x) = `((x + 1)/(x - 1))`, then prove that f(f(x)) = x.
If f(x) = ex and g(x) = loge x then find (fg)(1).
Draw the graph of the following function:
f(x) = |x – 2|
Draw the graph of y = 9 - x2.
If f(x) = `{(x^2 - 4x if x >= 2),(x+2 if x < 2):}`, then f(5) is
The graph of y = 2x2 is passing through:
Which one of the following functions has the property f(x) = `"f"(1/x)`?
The range of f(x) = |x|, for all x ∈ R is:
If f(x) = x2 and g(x) = 2x + 1 then (fg)(0) is:
