Advertisements
Advertisements
प्रश्न
Draw the graph of the following function:
f(x) = e2x
Advertisements
उत्तर
For x = 0, f(x) becomes 1 i.e., the curve cuts the y-axis at y = 1.
For no real value of x, f(x) equals to 0. Thus it does not meet the x-axis for real values of x.

APPEARS IN
संबंधित प्रश्न
Determine whether the following function is odd or even?
f(x) = `((a^x - 1)/(a^x + 1))`
Determine whether the following function is odd or even?
f(x) = `log (x^2 + sqrt(x^2 + 1))`
If f(x) = `x^3 - 1/x^3`, then show that `"f"(x) + "f"(1/x)` = 0
Draw the graph of the following function:
f(x) = x |x|
If f(x) = `{(x^2 - 4x if x >= 2),(x+2 if x < 2):}`, then f(5) is
The graph of y = 2x2 is passing through:
The graph of y = ex intersect the y-axis at:
The minimum value of the function f(x) = |x| is:
Which one of the following functions has the property f(x) = `"f"(1/x)`?
The range of f(x) = |x|, for all x ∈ R is:
