Advertisements
Advertisements
प्रश्न
Determine the ratio in which the point P (m, 6) divides the join of A(−4, 3) and B(2, 8). Also, find the value of m.
Determine the ratio in which the point P(m, 6) divides the line segment joining the points A (−4, 3) and B (2, 8). Also, find the value of m.
Advertisements
उत्तर
The co-ordinates of a point which divides two points (x1, y1) and (x2, y2) internally in the ratio m : n are given by the formula,
`(x, y) = ((mx_2 + nx_1) / (m + 2))"," ((my_2 + ny_1) / (m + n))`
Here, we are given that the point P(m, 6) divides the line joining the points A(−4, 3) and B(2, 8) in some ratio.
Let us substitute these values in the earlier-mentioned formula.
`(m, 6) = ((m(2) + n(-4)) / (m + n)), ((m(8) + n(3)) / (m + n))`
Equating the individual components, we have
`6 = ((m(8) + n(3)) / (m + n))`
6m + 6n = 8m + 3n
2m = 3n
`m / n = 3 / 2`
We see that the ratio in which the given point divides the line segment is 3 : 2.
Let us now use this ratio to find out the value of m.
`(m, 6) = ((m(2) + n(4)) / (m = n)), ((m(8) + n(3)) / (m + n))`
`(m, 6) = ((3(2) + 2(-4)) / (3 + 2)), ((3(8) + 2(3)) / (3 + 2))`
Equating the individual components, we have
`m = (3(2) + 2(4)) / (3 + 2)`
`m = -2 / 5`
Thus, the value of m is `- 2 / 5` and m : n = 3 : 2.
संबंधित प्रश्न
If A(–2, 1), B(a, 0), C(4, b) and D(1, 2) are the vertices of a parallelogram ABCD, find the values of a and b. Hence find the lengths of its sides
The coordinates of the point P are (−3, 2). Find the coordinates of the point Q which lies on the line joining P and origin such that OP = OQ.
Find the coordinates of the point where the diagonals of the parallelogram formed by joining the points (-2, -1), (1, 0), (4, 3) and(1, 2) meet
The line segment joining the points A(3,−4) and B(1,2) is trisected at the points P(p,−2) and Q `(5/3,q)`. Find the values of p and q.
Find the coordinates of the centre of the circle passing through the points P(6, –6), Q(3, –7) and R (3, 3).
If `P(a/2,4)`is the mid-point of the line-segment joining the points A (−6, 5) and B(−2, 3), then the value of a is
Show that `square` ABCD formed by the vertices A(-4,-7), B(-1,2), C(8,5) and D(5,-4) is a rhombus.
The measure of the angle between the coordinate axes is
The ordinate of any point on x-axis is
The perpendicular distance of the point P (4, 3) from x-axis is
The perpendicular distance of the P (4,3) from y-axis is
Prove hat the points A (2, 3) B(−2,2) C(−1,−2), and D(3, −1) are the vertices of a square ABCD.
In \[∆\] ABC , the coordinates of vertex A are (0, - 1) and D (1,0) and E(0,10) respectively the mid-points of the sides AB and AC . If F is the mid-points of the side BC , find the area of \[∆\] DEF.
If R (x, y) is a point on the line segment joining the points P (a, b) and Q (b, a), then prove that x + y = a + b.
Write the coordinates the reflections of points (3, 5) in X and Y -axes.
Find the distance between the points \[\left( - \frac{8}{5}, 2 \right)\] and \[\left( \frac{2}{5}, 2 \right)\] .
The distance between the points (a cos 25°, 0) and (0, a cos 65°) is
The distance between the points (a cos θ + b sin θ, 0) and (0, a sin θ − b cos θ) is
The ratio in which the x-axis divides the segment joining (3, 6) and (12, −3) is
The distance of the point (4, 7) from the x-axis is
If A(x, 2), B(−3, −4) and C(7, −5) are collinear, then the value of x is
What is the nature of the line which includes the points (-5, 5), (6, 5), (-3, 5), (0, 5)?
Which of the points P(-1, 1), Q(3, - 4), R(1, -1), S (-2, -3), T(-4, 4) lie in the fourth quadrant?
If segment AB is parallel Y-axis and coordinates of A are (1, 3), then the coordinates of B are ______.
Abscissa of all the points on the x-axis is ______.
The points (–5, 2) and (2, –5) lie in the ______.
Which of the points P(0, 3), Q(1, 0), R(0, –1), S(–5, 0), T(1, 2) do not lie on the x-axis?
The distance of the point (–4, 3) from y-axis is ______.
The distance of the point (–1, 7) from x-axis is ______.
