मराठी

Find the Third Vertex of a Triangle, If Two of Its Vertices Are at (−3, 1) and (0, −2) and the Centroid is at the Origin. - Mathematics

Advertisements
Advertisements

प्रश्न

Find the third vertex of a triangle, if two of its vertices are at (−3, 1) and (0, −2) and the centroid is at the origin.

 

 
Advertisements

उत्तर

 

We have to find the co-ordinates of the third vertex of the given triangle. Let the co-ordinates of the third vertex be(x,y).

The co-ordinates of other two vertices are (−3, 1) and (0, −2)

The co-ordinate of the centroid is (0, 0)

We know that the co-ordinates of the centroid of a triangle whose vertices are   

`(x_1,y_1),(x_2,y_2),(x_3,y_3)`is 

`((x_1+x_2+x_3)/3,(y_1+y_2+y_3)/3)` 

So, 

`(0,0)=((x+0-0)/3,(y+1-2)/3)` 

Compare individual terms on both the sides- 

`(x-3)/3=0` 

So, 

x=3 

Similarly, 

`(y-1)/3=0` 

So, 

y=1 

So the co-ordinate of third vertex (3,1) 

 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-Ordinate Geometry - Exercise 6.4 [पृष्ठ ३७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.4 | Q 3 | पृष्ठ ३७

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Prove that the points (3, -2), (4, 0), (6, -3) and (5, -5) are the vertices of a parallelogram.


Show that the following points are the vertices of a square:

A (0,-2), B(3,1), C(0,4) and D(-3,1)


Points P, Q, R and S divide the line segment joining the points A(1,2) and B(6,7) in five equal parts. Find the coordinates of the points P,Q and R


ABCD is rectangle formed by the points A(-1, -1), B(-1, 4), C(5, 4) and D(5, -1). If P,Q,R and S be the midpoints of AB, BC, CD and DA respectively, Show that PQRS is a rhombus.


If `P(a/2,4)`is the mid-point of the line-segment joining the points A (−6, 5) and B(−2, 3), then the value of a is


Show that A(-4, -7), B(-1, 2), C(8, 5) and D(5, -4) are the vertices of a
rhombus ABCD.


The abscissa of any point on y-axis is


If the point P(x, 3) is equidistant from the point A(7, −1) and B(6, 8), then find the value of x and find the distance AP.   


If R (x, y) is a point on the line segment joining the points P (a, b) and Q (b, a), then prove that y = a + b.


Write the perimeter of the triangle formed  by the points O (0, 0), A (a, 0) and B (0, b).

 

If A (5, 3), B (11, −5) and P (12, y) are the vertices of a right triangle right angled at P, then y=


The line segment joining points (−3, −4), and (1, −2) is divided by y-axis in the ratio. 


If the line segment joining the points (3, −4), and (1, 2) is trisected at points P (a, −2) and Q \[\left( \frac{5}{3}, b \right)\] , Then,

 


If segment AB is parallel Y-axis and coordinates of A are (1, 3), then the coordinates of B are ______


Point (–10, 0) lies ______.


A point both of whose coordinates are negative will lie in ______.


Find the coordinates of the point which lies on x and y axes both.


Seg AB is parallel to X-axis and coordinates of the point A are (1, 3), then the coordinates of the point B can be ______.


Assertion (A): The ratio in which the line segment joining (2, -3) and (5, 6) internally divided by x-axis is 1:2.

Reason (R): as formula for the internal division is `((mx_2 + nx_1)/(m + n) , (my_2 + ny_1)/(m + n))`


The distance of the point (–6, 8) from x-axis is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×