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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Describe the preparation of potassium permanganate. How does the acidified permanganate solution react with iron (II) ions? Write the ionic equation for the reaction.

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प्रश्न

Describe the preparation of potassium permanganate. How does the acidified permanganate solution react with iron (II) ions? Write the ionic equation for the reaction.

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सविस्तर उत्तर
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उत्तर

Potassium permanganate is prepared by fusion of MnO2 with an alkali metal hydroxide and an oxidising agent like KNO3. This produces the dark green K2MnO4, which disproportionates in a neutral or acidic solution to give permanganate.

\[\ce{2MnO2 + 4KOH + O2 -> 2K2MnO4 + 2H2O}\]

Potassium manganate is extracted with water and thereafter disproportionates in neutral or acidic solution to yield potassium permanganate.

\[\ce{3MnO^{2-}_4 + 4H^+ -> 2MnO^-_4 + MnO2 + 2H2O}\]

In an acidic medium of dilute sulphuric acid, KMnO4 acts as a strong oxidising agent, and it reacts as:

\[\ce{MnO^-_4 + 8H^+ + 5e- -> Mn^2+ + 4H2O}\]

Ferrous (Fe2+) ion solution to ferric (Fe3+) ion solution

\[\ce{MnO^-_4 + 8H+ + 5e- -> Mn^{2+} + 4H2O}\]

\[\ce{5Fe^{2+} -> 5Fe^{3+} + 5e-}\]
________________________________________________
\[\ce{MnO^-_4 + 5Fe^{2+} + 8H+ -> Mn^{2+} + 5Fe^{3+} + 4H2O}\]

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पाठ 4: d-and ƒ-Block Elements - 'NCERT TEXT-BOOK, Exercises [पृष्ठ ५०६]

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संबंधित प्रश्‍न

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When MnO2 is fused with KOH in the presence of KNO3 as an oxidizing agent, it gives a dark green compound (A). Compound (A) disproportionates in an acidic solution to give a purple compound (B).  An alkaline solution of compound (B) oxidizes KI to compound (C) whereas an acidified solution of compound (B) oxidizes KI to (D). Identify (A), (B), (C), and (D).


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(a) \[\ce{Cu^{+} -> Cu^{2+} + Cu}\]

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(c) \[\ce{2KMnO4 -> K2MnO4 + MnO2 + O2}\]

(d) \[\ce{2MnO^{-}4 + 3Mn^{2+} + 2H2O -> 5MnO2 + 4H^{+}}\]


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