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प्रश्न
Define seasonal index
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उत्तर
Seasonal Index for every season (monthly or quarterly) is calculated as follows
Seasonal Index (S.I) = `"Seasonal Average"/"Grand Average" xx 100`
If the data is given monthwise
Seasonal Index = `"Monthly Average"/"Grand Average" xx 100`
If quarterly data is given
Seasonal Index = `"Quarterly Average"/"Grand Average" xx 100`
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संबंधित प्रश्न
What is the need for studying time series?
State the uses of time series
Define secular trend
Discuss about irregular variation
Find the trend of production by the method of a five-yearly period of moving average for the following data:
| Year | Production ('000) |
| 1979 | 126 |
| 1980 | 123 |
| 1981 | 117 |
| 1982 | 128 |
| 1983 | 125 |
| 1984 | 124 |
| 1985 | 130 |
| 1986 | 114 |
| 1987 | 122 |
| 1988 | 129 |
| 1989 | 118 |
| 1990 | 123 |
The annual production of a commodity is given as follows:
| Year | production (in tones) |
| 1995 | 155 |
| 1996 | 162 |
| 1997 | 171 |
| 19988 | 182 |
| 1999 | 158 |
| 2000 | 880 |
| 2001 | 178 |
Fit a straight line trend by the method of least squares
Choose the correct alternative:
The value of ‘b’ in the trend line y = a + bx is
Fit a straight line trend by the method of least squares to the following data
| Year | 1980 | 1981 | 1982 | 1983 | 1984 | 1985 | 1986 | 1987 |
| Sales | 50.3 | 52.7 | 49.3 | 57.3 | 56.8 | 60.7 | 62.1 | 58.7 |
The sum of the infinite series `x + (1 + 2)/(2!) x^2 + (1 + 2 + 3)/(3!) x^3 +` .... equals
Let An be the sum of the first n terms of the geometric series `704 + 704/2 + 704/4 + 704/8 + ...` and Bn be the sum of the first n terms of the geometric series `1984 - 1984/2 + 1984/4 + 1984/8 + ...` If An = Bn, then the value ofn is (where n ∈ N).
