Advertisements
Advertisements
प्रश्न
Construct a parallelogram ABCD such that l(BC) = 7 cm, m∠ABC = 40° , l(AB) = 3 cm.
Advertisements
उत्तर
Steps of Construction:
Step 1: Draw AB = 3 cm.
Step 2: Draw ∠ABX = 40°
Step 3: With B as the center and radius 7 cm, draw an arc cutting the ray BX at C.
Step 4: With C as centre and radius 3 cm, draw an arc.
Step 5: With A as the center and a radius of 7 cm, draw an arc cutting the previous arc at D.
Step 6: Join AD and CD.

Here, ABCD is the required parallelogram.
संबंधित प्रश्न
Given a parallelogram ABCD. Complete each statement along with the definition or property used.

- AD = ______
- ∠DCB = ______
- OC = ______
- m∠DAB + m∠CDA = ______
Name the quadrilaterals whose diagonals bisect each other
Referring the adjacent figure of a parallelogram, write the answer of questions given below.

(1) If l(WZ) = 4.5 cm then l(XY) = ?
(2) If l(YZ) = 8.2 cm then l(XW) = ?
(3) If l(OX) = 2.5 cm then l(OZ) = ?
(4) If l(WO) = 3.3 cm then l(WY) = ?
(5) If m∠WZY = 120° then m∠WXY = ? and m∠XWZ = ?
ABCD is a parallelogram. What kind of quadrilateral is it if: AC is perpendicular to BD but is not equal to it?
ABCD is a parallelogram. What kind of quadrilateral is it if: AC = BD but AC is not perpendicular to BD?
In the following diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilateral ABCD.

Show that:
(i) ∠PSB + ∠SPB = 90°
(ii) ∠PBS = 90°
(iii) ∠ABC = 90°
(iv) ∠ADC = 90°
(v) ∠A = 90°
(vi) ABCD is a rectangle
Thus, the bisectors of the angles of a parallelogram enclose a rectangle.
The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that DM = BN.

Prove that:
(i) ∆DMC = ∆BNA and so CM = AN
(ii) ∆AMD = ∆CNB and so AM CN
(iii) ANCM is a parallelogram.
Iron rods a, b, c, d, e, and f are making a design in a bridge as shown in the figure. If a || b, c || d, e || f, find the marked angles between d and f
In parallelogram MODE, the bisector of ∠M and ∠O meet at Q, find the measure of ∠MQO.
Construct a parallelogram ABCD in which AB = 4 cm, BC = 5 cm and ∠B = 60°.
