मराठी

Complete the following: In case of non-polar covalent bond, the covalent bond is formed in the ______ of atoms and shared electrons are ______ distributed. (corner, middle, equally, unequally)

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प्रश्न

Complete the following:

In case of non-polar covalent bond, the covalent bond is formed in the ______ of atoms and shared electrons are ______ distributed. (corner, middle, equally, unequally)

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उत्तर

In case of non-polar covalent bond, the covalent bond is formed in the middle of atoms and shared electrons are equally distributed

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पाठ 2: Chemical Bonding - EXERCISE-2 [पृष्ठ ३५]

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एस.पी. सिंह Concise Chemistry [English] Class 10 ICSE
पाठ 2 Chemical Bonding
EXERCISE-2 | Q 6. (b) | पृष्ठ ३५

संबंधित प्रश्‍न

Choose the most appropriate answer from the following list of oxides which fit the description.

A covalent oxide of a metalloid.


Explain why, graphite can be used as a lubricant but diamond cannot.


State any two uses of diamond.


 What is graphite?


Define a covalent bond.


Observe the straight chain hydrocarbons given below and answer the following
questions :
i) Which of the straight chain compounds from A and B is saturated and  unsaturated straight chains?
ii) Name these straight chains.
iii) Write their chemical formulae and number of – CH2 - units.


Explain the following:

Water is a polar covalent molecule.


Write a short note.

Characteristics of carbon


Which of the following are correct structural isomers of butane?

  1. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - C - H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

  2. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}|\phantom{.....}|\\
    \ce{H}\ce{H-C-H}\ce{H}\\
    |\\
    \ce{H}\\
    \end{array}\]
  3. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}\backslash\phantom{..}|\\
    \phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
    \phantom{.......}|\\
    \phantom{.......}\ce{H}\\
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

Explain dipole (polar) molecule by taking hydrogen chloride as an example.


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