Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
1 + tan2 θ = ?
पर्याय
Sin2 θ
Sec2 θ
Cosec2 θ
Cot2 θ
Advertisements
उत्तर
sec2θ
Explanation:
1 + tan2θ = sec2θ
APPEARS IN
संबंधित प्रश्न
Prove the following identities:
`( i)sin^{2}A/cos^{2}A+\cos^{2}A/sin^{2}A=\frac{1}{sin^{2}Acos^{2}A)-2`
`(ii)\frac{cosA}{1tanA}+\sin^{2}A/(sinAcosA)=\sin A\text{}+\cos A`
`( iii)((1+sin\theta )^{2}+(1sin\theta)^{2})/cos^{2}\theta =2( \frac{1+sin^{2}\theta}{1-sin^{2}\theta } )`
Prove the following trigonometric identities.
if `T_n = sin^n theta + cos^n theta`, prove that `(T_3 - T_5)/T_1 = (T_5 - T_7)/T_3`
Prove the following trigonometric identities.
`(cos A cosec A - sin A sec A)/(cos A + sin A) = cosec A - sec A`
Prove the following identities:
`((1 + tan^2A)cotA)/(cosec^2A) = tan A`
Prove the following identities:
`sqrt((1 - cosA)/(1 + cosA)) = cosec A - cot A`
If `( sin theta + cos theta ) = sqrt(2) , " prove that " cot theta = ( sqrt(2)+1)`.
If ` cot A= 4/3 and (A+ B) = 90° ` ,what is the value of tan B?
If x = a cos θ and y = b sin θ, then b2x2 + a2y2 =
Prove the following identity:
`cosA/(1 + sinA) = secA - tanA`
Prove the following identity :
`(cotA + tanB)/(cotB + tanA) = cotAtanB`
If x = r sinA cosB , y = r sinA sinB and z = r cosA , prove that `x^2 + y^2 + z^2 = r^2`
If cosθ = `5/13`, then find sinθ.
Evaluate:
`(tan 65^circ)/(cot 25^circ)`
Prove that identity:
`(sec A - 1)/(sec A + 1) = (1 - cos A)/(1 + cos A)`
Prove that: sin6θ + cos6θ = 1 - 3sin2θ cos2θ.
tan (90 – θ) = ?
If `tan θ = 9/40`, complete the activity to find the value of sec θ.
Activity:
sec2θ = 1 + `square` ...[Fundamental trigonometric identity]
sec2θ = 1 + `square^2`
sec2θ = 1 + `square`
sec θ = `square`
The value of tan A + sin A = M and tan A - sin A = N.
The value of `("M"^2 - "N"^2) /("MN")^0.5`
Prove the following:
`tanA/(1 + sec A) - tanA/(1 - sec A)` = 2cosec A
Prove the following:
`1 + (cot^2 alpha)/(1 + "cosec" alpha)` = cosec α
