मराठी

If ` Cot A= 4/3 and (A+ B) = 90° ` ,What is the Value of Tan B? - Mathematics

Advertisements
Advertisements

प्रश्न

If ` cot A= 4/3 and (A+ B) = 90°  `  ,what is the value of tan B?

Advertisements

उत्तर

We have ,

`cot A = 4/3`

 ⇒ ` cot (90° - B ) = 4/3                (As , A+ B = 90° )`

∴ tanB = `4/3`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Trigonometric Identities - Exercises 3

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 8 Trigonometric Identities
Exercises 3 | Q 24

संबंधित प्रश्‍न

Prove the following trigonometric identities.

`tan theta - cot theta = (2 sin^2 theta - 1)/(sin theta cos theta)`


Prove the following identities:

`tan A - cot A = (1 - 2cos^2A)/(sin A cos A)`


Show that : tan 10° tan 15° tan 75° tan 80° = 1


If sec A + tan A = p, show that:

`sin A = (p^2 - 1)/(p^2 + 1)`


` tan^2 theta - 1/( cos^2 theta )=-1`


`(cos  ec^theta + cot theta )/( cos ec theta - cot theta  ) = (cosec theta + cot theta )^2 = 1+2 cot^2 theta + 2cosec theta  cot theta`


Write the value of ` sec^2 theta ( 1+ sintheta )(1- sintheta).`


If `secθ = 25/7 ` then find tanθ.


\[\frac{\tan \theta}{\sec \theta - 1} + \frac{\tan \theta}{\sec \theta + 1}\] is equal to 


If cos A + cos2 A = 1, then sin2 A + sin4 A =


Prove the following identity :

secA(1 + sinA)(secA - tanA) = 1


Prove the following identity :

`tanA - cotA = (1 - 2cos^2A)/(sinAcosA)`


Prove the following identities.

sec6 θ = tan6 θ + 3 tan2 θ sec2 θ + 1


Prove the following identities.

(sin θ + sec θ)2 + (cos θ + cosec θ)2 = 1 + (sec θ + cosec θ)2


If sin θ + sin2 θ = 1 show that: cos2 θ + cos4 θ = 1


Prove that `"cosec"  θ xx sqrt(1 - cos^2theta)` = 1


Prove that `"cot A"/(1 - cot"A") + "tan A"/(1 - tan "A")` = – 1


If cosec A – sin A = p and sec A – cos A = q, then prove that `("p"^2"q")^(2/3) + ("pq"^2)^(2/3)` = 1


Prove the following identity:

(sin2θ – 1)(tan2θ + 1) + 1 = 0


`1/sin^2θ - 1/cos^2θ - 1/tan^2θ - 1/cot^2θ - 1/sec^2θ - 1/("cosec"^2θ) = -3`, then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×