मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Can a Gravitational Field Be Added Vectorially to an Electric Field to Get a Total Field? - Physics

Advertisements
Advertisements

प्रश्न

Can a gravitational field be added vectorially to an electric field to get a total field?

एका वाक्यात उत्तर
Advertisements

उत्तर

No, a gravitational field cannot be added vectorially to an electric field.
This is because for electric influence, one or both the bodies should have some net charge and for gravitational influence both the bodies should have some mass. Also, gravitational field is a weak force,while electric field is a strong force.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Electric Field and Potential - Short Answers [पृष्ठ ११९]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 7 Electric Field and Potential
Short Answers | Q 4 | पृष्ठ ११९

संबंधित प्रश्‍न

A hollow cylindrical box of length 0.5 m and area of cross-section 25 cm2 is placed in a three dimensional coordinate system as shown in the figure. The electric field in the region is given by `vecE = 20 xhati`  where E is NC­−1 and x is in metres. Find

(i) Net flux through the cylinder.

(ii) Charge enclosed by the cylinder.


In some old texts it is mentioned that 4π lines of force originate from each unit positive charge. Comment on the statement in view of the fact that 4π is not an integer. 


The electric field at the origin is along the positive x-axis. A small circle is drawn with the centre at the origin, cutting the axes at points A, B, C and D with coordinates (a, 0), (0, a), (−a, 0), (0, −a), respectively. Out of the points on the periphery of the circle, the potential is minimum at  


If a body is charged by rubbing it, its weight


Consider the situation in the figure. The work done in taking a point charge from P to Ais WA, from P to B is WB and from P to C is WC


The electric field in a region is directed outward and is proportional to the distance rfrom the origin. Taking the electric potential at the origin to be zero, 


Consider a uniformly charged ring of radius R. Find the point on the axis where the electric field is maximum.

 

A wire is bent in the form of a regular hexagon and a total charge q is distributed uniformly on it. What is the electric field at the centre? You may answer this part without making any numerical calculations. 


12 J of work has to be done against an existing electric field to take a charge of 0.01 C from A to B. How much is the potential difference  VB − VA


An electric field  \[\vec{E}  =  \vec{i}\]  Ax exists in space, where A = 10 V m−2. Take the potential at (10 m, 20 m) to be zero. Find the potential at the origin.


The kinetic energy of a charged particle decreases by 10 J as it moves from a point at potential 100 V to a point at potential 200 V. Find the charge on the particle.  


Which of the following methods can be used to charge a metal sphere positively without touching it? Select the most appropriate.


The unit of electric field is not equivalent to ______.

A charged particle is free to move in an electric field. It will travel ______.

For distance far away from centre of dipole the change in magnitude of electric field with change in distance from the centre of dipole is ______.

In general, metallic ropes are suspended on the carriers taking inflammable materials. The reason is ______.


When 1014 electrons are removed from a neutral metal sphere, the charge on the sphere becomes ______.


The Electric field at a point is ______.

  1. always continuous.
  2. continuous if there is no charge at that point.
  3. discontinuous only if there is a negative charge at that point.
  4. discontinuous if there is a charge at that point.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×