मराठी

Can a quadrilateral ABCD be a parallelogram if ∠D + ∠B = 180°?

Advertisements
Advertisements

प्रश्न

Can a quadrilateral ABCD be a parallelogram if ∠D + ∠B = 180°?

लघु उत्तर
Advertisements

उत्तर

For ∠D + ∠B = 180°, quadrilateral ABCD may or may not be a parallelogram. Along with this condition, the following conditions should also be fulfilled.

The sum of the measures of adjacent angles should be 180º.

Opposite angles should also be of same measures.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Understanding Quadrilaterals - EXERCISE 3.3 [पृष्ठ ३१]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 8
पाठ 3 Understanding Quadrilaterals
EXERCISE 3.3 | Q 3. (i) | पृष्ठ ३१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Given a parallelogram ABCD. Complete each statement along with the definition or property used.

  1. AD = ______
  2. ∠DCB = ______
  3. OC = ______
  4. m∠DAB + m∠CDA = ______

Consider the given parallelograms. Find the values of the unknowns x, y, z.


In the given figure, G is the point of concurrence of medians of ΔDEF. Take point H on ray DG such that D-G-H and DG = GH, then prove that `square`GEHF is a parallelogram.


Referring the adjacent figure of a parallelogram, write the answer of questions given below.

(1) If l(WZ) = 4.5 cm then l(XY) = ?

(2) If l(YZ) = 8.2 cm then l(XW) = ?

(3) If l(OX) = 2.5 cm then l(OZ) = ?

(4) If l(WO) = 3.3 cm then l(WY) = ?

(5) If m∠WZY = 120° then m∠WXY = ? and m∠XWZ = ?


Prove that the diagonals of a parallelogram bisect each other.


In parallelogram ABCD, E is the mid-point of AD and F is the mid-point of BC. Prove that BFDE is a parallelogram.


The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that DM = BN.

Prove that:
(i) ∆DMC = ∆BNA and so CM = AN
(ii) ∆AMD = ∆CNB and so AM CN
(iii) ANCM is a parallelogram.


If a triangle and a parallelogram lie on the same base and between the same parallels, then prove that the area of the triangle is equal to half of the area of parallelogram


ABCD is a parallelogram. The bisector of angle A intersects CD at X and bisector of angle C intersects AB at Y. Is AXCY a parallelogram? Give reason.


Draw a rough figure of a quadrilateral that is not a parallelogram but has exactly two opposite angles of equal measure.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×