Advertisements
Advertisements
प्रश्न
Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C3H5).
(Atomic mass: C = 14, O = 16, H = 1, Molar Volume = 22.4 dm3 at STP.)
Advertisements
उत्तर
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
Molar weight of propane = 12 × 3 + 8 = 44
Volume of 5O2 = 5 × 22.4 = 112 litres
44 g of propane requires = 112 litres of oxygen
1 g of propane requires = `112/44` litres
8.8 g of propane requires = `112/44 xx 8.8`
= 112 × 0.2
= 22.4 litres
APPEARS IN
संबंधित प्रश्न
Prove the Following :
2 X V.D. = Molecular mass.
Potassium nitrate on strong heating decomposes as under :
2KNO3 → 2KNO2 + O2
Calculate : Weight of oxygen formed when 5.05g of potassium nitrate decomposes completely.
(K = 39, 0 = 16, N = 14)
What weight of sulphuric acid will be required to dissolve 3g of magnesium carbonate?
[Mg = 24, C =12, 0 = 16 ]
MgCO3 + H2SO4 → MgSO4 + H2O+ CO2
An organic compound has the following percentage composition: C = 12.76%, H = 2.13%, Br = 85.11%. The vapour density of the compound is 94. Find out its molecular formula.
When heated, potassium permanganate decomposes according to the following equation:
\[\ce{2KMnO4 -> \underset{solid residue}{K2MnO4 + MnO2} + O2}\]
Some potassium permanganate was heated in test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.
Explain the term:
Vapour density
Calculate the relative molecular mass of:
Ammonium chloroplatinate (NH4)2 PtCl6
The mass of 5.6 litres of a certain gas at S.T.P. is 12 g. What is the relative molecular mass or molar mass of the gas?
If a crop of wheat removes 20 kg of nitrogen per hectare of soil, what mass of the fertilizer, calcium nitrate Ca(NO3)2 would be required to replace the nitrogen in a 10 hectare field?
The vapour density of CH3OH is ______. (At. Wt. C = 12, H = 1, O = 16)
