मराठी

Prove the Following :

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प्रश्न

Prove the Following :
2 X V.D. = Molecular mass.

एका वाक्यात उत्तर
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उत्तर

The molecular mass of the given compound is determined experimentally by  vapour density method also, in which the vapour density of the compound is determined. Vapour density is related to molecular mass as :
Molecular mass = 2 x vapour density.

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पाठ 5: Mole Concept and Stoichiometry - Exercise 1 [पृष्ठ ११५]

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फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept and Stoichiometry
Exercise 1 | Q 1.2 | पृष्ठ ११५

संबंधित प्रश्‍न

Define the term:

Vapour density


Potassium nitrate on strong heating decomposes as under :
2KNO3 → 2KNO2 + O2
Calculate : Weight of oxygen formed when 5.05g of potassium nitrate decomposes completely.
(K = 39, 0 = 16, N = 14)


Concentrated nitric acid oxidizes phosphorous to phosphoric acid according to the following equation :
P + 5HNO3 → H3PO4 + H2O + 5NO2
What mass of phosphoric acid can be prepared from 6 .2 g of phosphorous?


Samples of the gases O2, N2, CO2 and CO under the same conditions of temperature and pressure contain the same number of molecules represented by X. The molecules of Oxygen, occupy V litres and have a mass of 8 g. Under the same conditions of temperature and pressure :
What is the mass of CO2 in g?


Explain the term:

Vapour density


Calculate the relative molecular mass of:

(NH4)2SO4


Calculate the relative molecular mass of:

CHCl3 


A gas cylinder can hold 1 kg of hydrogen at room temperature and pressure. What mass of carbon dioxide can it hold under similar conditions of temperature and pressure?


When heated, potassium permanganate decomposes according to the following equation :

\[\ce{2KMnO4 -> \underset{\text{solid residue}}{K2MnO4 + MnO2} + O2}\]

(a) Some potassium permanganate was heated in the test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.

(b) Given that the molecular mass of potassium permanganate is 158. What volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 litres)


67.2 litres of hydrogen combines with 44.8 litres of nitrogen to form ammonia under specific conditions as:

\[\ce{N2_{(g)} + 3H2_{(g)} -> 2NH3_{(g)}}\]

Calculate the volume of ammonia produced. What is the other substance, if any, that remains in the resultant mixture?


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