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प्रश्न
Answer the following giving reasons:
A p-n junction diode is damaged by a strong current.
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उत्तर
A strong current damages a p-n junction diode because it increases the semiconductor's temperature as more power passes through it and some of that energy is converted to heat. The semiconductor then conducts more current as the temperature rises a little further, which raises the temperature even further. Higher temperature results in more current, which increases the temperature. In what is referred to as a thermal runaway, this cycle keeps repeating. The semiconductor (p-n junction) is ultimately destroyed.
संबंधित प्रश्न
Explain the working of P-N junction diode in forward and reverse biased mode.
The graph shown in the figure represents a plot of current versus voltage for a given semiconductor. Identify the region, if any, over which the semiconductor has a negative resistance.
With reference to a semiconductor diode, what is meant by:
(i) Forward bias
(ii) Reverse bias
(iii) Depletion region
Basic materials used in the present solid state electronic devices like diode, transistor, ICs, etc are ______.
Diffusion in a p-n junction is due to ______.
A – pn junction has a depletion layer of thickness .of the order of
When we apply reverse biased to a junction diode, it
The nature of binding for a crystal with alternate and evenly spaced positive and negatively ions is
Figure shows the transfer characteristics of a base biased CE transistor. Which of the following statements are true?
At Vi = 0.4 V, transistor is in active state.
At Vi = 1 V, it can be used as an amplifier.
At Vi = 0.5 V, it can be used as a switch turned off.
At Vi = 2.5 V, it can be used as a switch turned on.
In the depletion region of a diode ______.
- there are no mobile charges.
- equal number of holes and electrons exist, making the region neutral.
- recombination of holes and electrons has taken place.
- immobile charged ions exist.
