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प्रश्न
An AND gate can be prepared by repetitive use of
(a) NOT gate
(b) OR gate
(c) NAND gate
(d) NOR gate.
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उत्तर
(c) NAND gate
(d) NOR gate


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संबंधित प्रश्न
Which logic gate corresponds to the truth table given below?
|
A |
B |
Y |
|
0 |
0 |
I |
|
0 |
1 |
0 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
The output of NOR gate is high, when _______.
Write the truth table for the circuits given in following figure consisting of NOR gates only. Identify the logic operations (OR, AND, NOT) performed by the two circuits.
(a)

(b)

Give the truth table and circuit symbol for NAND gate
Identify the logic gate represented by the circuit as shown and write its truth table.

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Name the logic gate which generated high output when at least one input is high.
Let \[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\] Evaluate X for A = B = C = 0.
Show the variation of voltage with time, for a digital signal.
With the help of a diagram, show how you can use several NAND gates to obtain an OR gate.
Useful Constants and Relations :
| 1. Speed of Light in Vacuum | (c) = 3.00 x 108 m/s |
| 2. Charge of a proton | (e) = 1.60 x 10-19C |
| 3. Planck's Constant | (h) = 6.6 x 10-34 Js |
| 4. Permeability of vacuum | (μ0) = 4π x 10-7 Hm-1 |
| 5. Electron Volt | (1eV ) = 1.6 x 10 |
| 6. Unified Atomic Mass Unit | (1u) = 931 MeV |
| (π) = 3.14 | |
| ( ln 2 ) = 0.693 |
NAND and NOR gates are called universal gates primarily because they ______.
A radar is sending out pules of 1 micro second duration at interval of 100 micro-second. The range of the radar is
In potential barrier development in a junction diode opposes
Two car garages have a common gate which needs to open automatically when a car enters either of the garages or cars enter both. Devise a circuit that resembles this situation using diodes for this situation.
The given figure shows the waveforms for two inputs A and B and that for the output Y of a logic circuit. The logic circuit is ______.
A logic circuit provides the output Y as per the following truth table:
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
The expression for the output Y is:
