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प्रश्न
Account for the following.
pKb of aniline is more than that of methylamine.
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उत्तर
In aniline, the lone pair of electrons on the N-atom is delocalized over the benzene ring. As a result electron density on the nitrogen decreases. In contrast in CH3NH2, the +I effect of CH3 increases the electron density on the N-atom. Therefore, aniline is a weaker base than methylamine and hence its pKb value is more than that of methyl amine.
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संबंधित प्रश्न
In the following
The compound ‘B’ is _______.
(A) Propan–1–amine
(B) Propan–2–amine
(C) Isopropylamine
(D) Dimethylamine
Give reasons for the following:
CH3NH2 is more basis than C6H5NH2.
Choose the most correct option.
Identify ‘B’ in the following reactions
\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
What is the action of nitrous acid on the following compounds?
Isopropyl amine
Write a short note on the following.
Schotten-Baumann reaction
How will you prepare propan-1-amine from butane nitrile?
Identify A, B and C.
\[\ce{CH3 - NO2 ->[LiAlH4] A ->[2CH3CH2Br] B ->[H2SO4] C}\]
(C2H5)2CHNH2. The following amine can be classified as:
Arrange the following in the increasing order of their basic strength:
C2H5NH2, C6H5NH2, (C2H5)2NH
Account for the following:
Aniline does not undergo Friedel-Crafts reaction.
