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प्रश्न
Account for the following:
Eu2+ with electronic configuration [Xe]4f76s2 is a strong reducing agent.
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उत्तर
Because it is more stable than Eu, Eu2+ is a powerful reducing agent. After removing two electrons, the electronic configuration is 4f76s2, resulting in a half-filled (f) electronic configuration that acts as a strong reducing agent.
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संबंधित प्रश्न
How would you account for the following?
Transition metals exhibit variable oxidation states.
Calculate magnetic moment of `Fe_((aq))^(2+) ion (Z=26).`
Write the factors which are related to the colour of transition metal ions.
Write the formula of an oxo-anion of Chromium (Cr) in which it shows the oxidation state equal to its group number
Dissociation of H2S is suppressed in acidic medium.
Electronic configuration of Mn2+ is ____________.
Transition elements form binary compounds with halogens. Which of the following elements will form \[\ce{MF3}\] type compounds?
(i) \[\ce{Cr}\]
(ii) \[\ce{Co}\]
(iii) \[\ce{Cu}\]
(iv) \[\ce{Ni}\]
Match the solutions given in Column I and the colours given in Column II.
| Column I (Aqueous solution of salt) |
Column II (Colour) |
| (i) \[\ce{FeSO2.7H2O}\] | (a) Green |
| (ii) \[\ce{NiCl2.4H2O}\] | (b) Light pink |
| (iii) \[\ce{MnCl2.4H2O}\] | (c) Blue |
| (iv) \[\ce{CoC12,6H2O}\] | (d) Pale green |
| (v) \[\ce{Cu2 Cl2}\] | (e) Pink |
| (f) Colourless |
Why are fluorides of transition metals more stable in their higher oxidation state as compared to the lower oxidation state?
Give a reason for the following:
Transition metals possess a great tendency to form complex compounds.
