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प्रश्न
In 3d series (Sc to Zn), which element has the lowest enthalpy of atomisation and why?
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उत्तर
In the 3d series, from Sc to Zn, only zinc has filled valence shells. The valence shell electronic configuration of Zn is 3d104s2. Due to the absence of unpaired electrons in ns and (n–1)d shells, the interatomic electronic bonding is the weakest in zinc. Consequently, zinc has the least enthalpy of atomisation in the 3d series of transition elements.
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संबंधित प्रश्न
The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co
Answer the following: Which element has the highest m.p?
How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.
How would you account for the following:
The d1 configuration is very unstable in ions.
Calculate the number of unpaired electrons in the following gaseous ions:
Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in an aqueous solution?
Account for the following :
Ti4+ is colourless whereas V4+ is coloured in an aqueous solutions.
Explain why transition metals and their compounds act as a catalyst.
\[\ce{KMnO4}\] acts as an oxidising agent in acidic medium. The number of moles of \[\ce{KMnO4}\] that will be needed to react with one mole of sulphide ions in acidic solution is ______.
Which of the following statements is not correct?
Which of the following characteristics of transition metals is associated with their catalytic activity?
Assertion (A): Transition metals have high enthalpy of atomisation.
Reason (R): Greater number of unpaired electrons in transition metals results in weak metallic bonding.
