Advertisements
Advertisements
प्रश्न
A weight lifted a load of 200 kgf to a height of 2.5 m in 5 s. calculate: (i) the work done, and (ii) the power developed by him. Take g= 10 N kg-1.
Advertisements
उत्तर
Given load m = 200kgf, displacement h = 25 m, time = 5s, g = 10 N kg-1
Now work done = 200 kgf x 25 = 50000 J
or power = `"work done"/"time taken" = 5000/5` = 1000 watt
APPEARS IN
संबंधित प्रश्न
Is it possible that a force is acting on a body but still the work done is zero? Explain giving one example.
How many watts equal one horse power?
The work done on an object does not depend on ______.
Define 'joule'.
On what factors does the work done by a force depend?
Fill in the boxe to show the corresponding energy transformation.
In what way does an ‘Ideal machine’ differ from a ‘Practical machine’?
An electric motor of power 100 W is used to drive the stirrer in a water bath. If 50% of the energy supplied to the motor is spent in stirring the water. Calculate the work done on the water in one minute.
A is a push or a pull ______.
