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प्रश्न
A straight metal wire crosses a magnetic field of flux 4 mWb in a time 0.4 s. Find the magnitude of the emf induced in the wire.
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उत्तर
Given data:
dΦ = 4 mWb = 4 × 10-3
dt = 0.4 s
induced emf ε = ?
ε = + `("d"phi)/"dt"`
`therefore = (4 xx 10^-3)/0.4 = 40/4 xx 10^-3`
ε = 10 mV
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संबंधित प्रश्न
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(c) aluminium
(d) steel
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(d) The current in L long after t = t0 is ε/R.
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