Advertisements
Advertisements
प्रश्न
A solid weighs 2.10 N in air. It has a relative density of 8.4. How much will the body weigh if placed: In water
Advertisements
उत्तर
Weight of solid in air = 2.10 N
Relative density of solid = 8.4
Now, Relative density = weight of solid in air/ loss of weight of solid in water.
Loss of weight of solid in water = weight of solid in air/ Relative density.
Loss of weight of solid in water = 2.10/8.4 = 0.25 N.
Weight of solid in water = weight in air - loss of weight in water
Weight of solid in water = 2.10 - 0.25 =1.85 N.
APPEARS IN
संबंधित प्रश्न
Fill the missing word in the blank spaces in the following statements:
Air moves from a region of __________ pressure to a region of ________ pressure.
What is the purpose of a barometer?
How is the reading of a barometer affected when it is taken to (i) a mine, and (ii) a hill?
Give reasons for the following:
As we go higher, the atmospheric pressure decreases.
Explain briefly the factors that affect Atmospheric Pressure.
State two advantages of an aneroid barometer.
How is the reading of a barometer affected when it is taken to: A mine
The highest air pressure at sea level was recorded at ______ Russia.
Define High pressure
