Advertisements
Advertisements
प्रश्न
The radius of the press plunger and pump plunger are in ratio of 50 : 4. If an effort of 20 kgf acts on the pump plunger, calculate the maximum effort which the press plunger can over come.
Advertisements
उत्तर
Effort acting on the pump plunger = E = 20 kgf
Load acting on the press plunger = L =?
So let radius of pump plunger = 50x = R and radius of press plunger = 4x = r
Now, `"L"/"E"=(π"R"^2)/(π"r"^2)`
`"L"/20=(50"x")^2/(4"x")^2=2500/16=625/4`
L = `625/4xx20`
L = 625 × 5
= 3125 kgf.
APPEARS IN
संबंधित प्रश्न
Explain the following :
Two holes are made in a completely filled sealed tin can to take out oil from it .
Why does the liquid rise in a syringe when its piston is pulled up?
How is the barometric height of a simple barometer affected if Its tube is pushed down into the trough of mercury?
State two uses of a barometer.
Give reasons for the following:
Temperature and pressure are inversely related to one another.
Select the correct option.
As we move upwards, the atmospheric pressure
Select the correct option.
The atmospheric pressure on the earth’s surface is approximately
Why do not we feel uneasy even under enormous pressure of the atmosphere above as?
Describe an experiment to demonstrate that air exerts pressure.
High pressure is called ______.
