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A Neutron Moving with a Speed υ Strikes a Hydrogen Atom in Ground State Moving Towards It with the Same Speed. Find the Minimum Speed of the Neutron for Which Inelastic (Completely - Physics

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प्रश्न

A neutron moving with a speed υ strikes a hydrogen atom in ground state moving towards it with the same speed. Find the minimum speed of the neutron for which inelastic (completely or partially) collision may take place. The mass of neutron = mass of hydrogen = 1.67 × 10−27 kg.v

बेरीज
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उत्तर

Given:

Mass of neutron, m = 1.67 × 10−27 kg

Since neutron is moving with velocity (v), its energy (E) is given by

`E = 1/2 mv ^2`

Let the energy absorbed be ∆E.

The condition for inelastic collision is given below:

`1/2mv^2 > 2 Delta E`

`rArr DeltaE < 1/4 mv^2`

Since 10.2 eV, energy is required for the first excited state.

`therefore DeltaE < 10.2 eV `

`therefore 10.2 eV < 1/4 mv^2`

Thus, minimum speed of the neutron is given by

`rArr v_min = sqrt((4xx10.2)/m eV`

`rArr v_min = sqrt((10.2xx1.6xx10^19xx4)/(1.67xx10^-27)`
= 6 × 10m/sec

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पाठ 21: Bohr’s Model and Physics of Atom - Exercises [पृष्ठ ३८५]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 21 Bohr’s Model and Physics of Atom
Exercises | Q 35 | पृष्ठ ३८५

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