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प्रश्न
A man spent Rs. 2800 on buying a number of plants priced at Rs x each. Because of the number involved, the supplier reduced the price of each plant by Rupee 1.The man finally paid Rs. 2730 and received 10 more plants. Find x.
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उत्तर
Amount spent = Rs. 2800
Price of each plant = Rs. x
Reduced price = Rs. (x – 1)
No. of plants in first case = `(2800)/x`
No. of plants received in second case = `(2800)/x + 10`
Amount paid = Rs. 2730
According to the condition,
`(2800/x + 10)(x - 1)` = 2730
⇒ `((2800 + 10x)(x - 1))/x` = 2730
⇒ (2800 + 10)(x – 1) = 2730x
⇒ 2800x – 2800 + 10x2 – 10x – 2730 = 0
⇒ 10x2 + 2800x – 10x – 2730x – 2800 = 0
⇒ 10x2 + 60x – 2800 = 0
⇒ x2 + 60x – 280 = 0 ...(Dividing by 10)
⇒ x2 + 20x – 14x – 280 = 0
⇒ x(x + 20) – 14(x + 20) = 0
⇒ (x + 20)(x – 14) = 0
Either x + 20 = 0,
then x = –20,
but it is not possible as it is in negative.
or
x – 14 = 0,
then x = 14.
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