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प्रश्न
Solve the equation using the factorisation method:
`(3x -2)/(2x -3) = (3x - 8)/(x + 4)`
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उत्तर
`(3x -2)/(2x - 3) = (3x - 8)/(x + 4)`
⇒ (3x – 2)(x + 4) = (2x – 3)(3x – 8)
⇒ 3x2 + 12x – 2x – 8 = 6x2 – 16x – 9x + 24
⇒ 3x2 + 10x – 8 = 6x2 – 25x + 24
⇒ 3x2 – 35x + 32 = 0
⇒ 3x2 – 32x – 3x + 32 = 0
⇒ x(3x – 32) – 1(3x – 32) = 0
⇒ (x – 1)(3x – 32) = 0
If x – 1 = 0 or 3x – 32 = 0
⇒ x = 1 or x = `32/3 = 10 2/3`
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