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प्रश्न
A job production unit has four jobs A, B, C, D which can be manufactured on each of the four machines P, Q, R and S. The processing cost of each job for each machine is given in the following table:
| Jobs | Machines (Processing Cost in ₹) |
|||
| P | Q | R | S | |
| A | 31 | 25 | 33 | 29 |
| B | 25 | 24 | 23 | 21 |
| C | 19 | 21 | 23 | 24 |
| D | 38 | 36 | 34 | 40 |
Find the optimal assignment to minimize the total processing cost.
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उत्तर
Step 1: Row minimum
Subtract the smallest element in each row from every element in its row. The matrix obtained is given below:
| Jobs | Machines (Processing Cost in ₹) |
|||
| P | Q | R | S | |
| A | 6 | 0 | 8 | 4 |
| B | 4 | 3 | 2 | 0 |
| C | 0 | 2 | 4 | 5 |
| D | 4 | 2 | 0 | 6 |
Step 2: Column minimum
Subtract the smallest element in each column of assignment matrix obtained in step 1 from every element in its column.
| Jobs | Machine (Processing Cost in ₹) |
|||
| P | Q | R | S | |
| A | 6 | 0 | 8 | 4 |
| B | 4 | 3 | 2 | 0 |
| C | 0 | 2 | 4 | 5 |
| D | 4 | 2 | 0 | 6 |
Step 3:
Draw minimum number of vertical and horizontal lines to cover all zeros.
First cover all rows and columns which have maximum number of zeros.
| Jons | Machines (Processing Cost in ₹) |
|||
| P | Q | R | S | |
| A | 6 | 0 | 8 | 4 |
| B | 4 | 3 | 2 | 0 |
| C | 0 | 2 | 4 | 5 |
| D | 4 | 2 | 0 | 6 |
Step 4:
From step 3, minimum number of lines covering all the zeros are 4, which is equal to order of the matrix, i.e., 4
∴ Select a row with exactly one zero, enclose that zero in () and cross out all zeros in its respective column.
Similarly, examine each row and column and mark the assignment ().
∴ The matrix obtained is as follows:
| Jobs | Machines (Processing Cost in ₹) |
|||
| P | Q | R | S | |
| A | 6 | 0 | 8 | 4 |
| B | 4 | 3 | 2 | 0 |
| C | 0 | 2 | 4 | 5 |
| D | 4 | 2 | 0 | 6 |
Step 5:
The matrix obtained in step 4 contains exactly one assignment for each row and column.
∴ Optimal assignment schedule is as follows:
| Jobs | Machines | Processing cost (₹) |
| A | Q | 25 |
| B | S | 21 |
| C | P | 19 |
| D | R | 34 |
∴ Total minimum processing cost = 25 + 21 + 19 + 34 = ₹ 99.
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संबंधित प्रश्न
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Service Time ( in hrs.)
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| A | B | C | D | |
| W | 41 | 72 | 39 | 52 |
| X | 22 | 29 | 49 | 65 |
| Y | 27 | 39 | 60 | 51 |
| Z | 45 | 50 | 48 | 52 |
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| M1 | 27 | 18 | ∞ | 20 | 21 |
| M2 | 31 | 24 | 21 | 12 | 17 |
| M3 | 20 | 17 | 20 | ∞ | 16 |
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| A | B | C | D | |
| P | 11 | 11 | 9 | 9 |
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| R | 12 | 17 | 13 | 8 |
| S | 16 | 14 | 16 | 12 |
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| I | II | III | IV | |
| A | 7 | 25 | 26 | 10 |
| B | 12 | 27 | 3 | 25 |
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| D | 18 | 25 | 23 | 9 |
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| Machine | ||||
| U | V | W | ||
| Jobs | A | 17 | 25 | 31 |
| B | 10 | 25 | 16 | |
| C | 12 | 14 | 11 | |
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| a | b | c | d | e | |
| A | 160 | 130 | 175 | 190 | 200 |
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| 2 | 12 | 19 | 39 | 55 | 71 | 40 | |
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| 5 | 19 | 30 | 29 | 16 | 20 | 33 | |
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| I | II | III | IV | V | |
| A | 150 | 120 | 175 | 180 | 200 |
| B | 125 | 110 | 120 | 150 | 165 |
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| D | 40 | 40 | 70 | 70 | 100 |
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| Job | Machines (Processing cost in ₹) |
|||
| I | II | III | IV | |
| P | 31 | 25 | 33 | 29 |
| Q | 25 | 24 | 23 | 21 |
| R | 19 | 21 | 23 | 24 |
| S | 38 | 36 | 34 | 40 |
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| 1 | 10 | 5 | 9 | 18 | 11 |
| 2 | 13 | 9 | 6 | 12 | 14 |
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