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प्रश्न
A hemisphere and a cone have equal bases. If their heights are also equal, then what is the ratio of their curved surfaces?
थोडक्यात उत्तर
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उत्तर
The base of the cone and hemisphere are equal. So radius of the two is also equal.
and
Height of the hemisphere = height of the cone
Then the slant height of the cone
`l = sqrt(r^2 + h^2)`
`= sqrt(r^2 + r^2)`
` = sqrt(2r^2)`
`= rsqrt2 ................ (1)`
Now, the curved surface area of
Hemisphere ` =2pir^2`
and
The curved surface area of cone `=pirl`
Putting the value of l from eq. (i)
We get
`=pirsqrt2 r`
`=pir^2 sqrt2 r `
Now,
`"C .S .A. of hemisphare"/"C.S.A. of cone" = (2pir^2)/(pirsqrt2)`
`=2/sqrt2 xx sqrt2/sqrt2`
`=(2sqrt2)/2`
`=sqrt2 :1`
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