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प्रश्न
A frustum of a right circular cone is of height 16 cm with radius of its ends as 8 cm and 20 cm. Then, the volume of the frustum is
पर्याय
3328π cm3
3228π cm3
3240π cm3
3340π cm3
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उत्तर
3328π cm3
Explanation;
Hint:
Here, h = 16 cm, r = 8 cm, R = 20 cm
Volume of the frustum
= `1/3pi"h"("R"^2 + "r"^2 + "Rr")`
= `1/3pi xx 16(20^2 + 8^2 + 20 xx 8)`
= `1/3 pi xx 16(400 + 64 + 160)`
= `1/3 pi xx 16 xx 624`
= π × 16 × 208
= 3328π cm3
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Find the total surface area of frustum, if its radii are 15 cm and 7 cm. Also, the slant height of the frustum is 14 cm.
Radii of the frustum = `square` cm and `square` cm
Slant height of the frustum = `square` cm
Total surface area = `π[(r_1^2 + r_2^2 + (r_1 + r_2)l]`
= `22/7 [square + square + (square + square) square]`
= `22/7 (square)`
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Hence, the total surface area of the frustum is `square`.
