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A Heave Uniform Rod is Hanging Vertically Form a Fixed Support. It is Stretched by Its Won Weight. the Diameter of the Rod is - Physics

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प्रश्न

A heave uniform rod is hanging vertically form a fixed support. It is stretched by its won weight. The diameter of the rod is

पर्याय

  •  smallest at the top and gradually increases down the rod

  •  largest at the top and gradually decreased down the rod

  • uniform everywhere

  • maximum in the middle.

MCQ
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उत्तर

As the rod is of uniform mass distribution and stretched by its own weight, the topmost part of the rod experiences maximum stress due to the weight of the entire rod. This stress leads to lateral strain and the rod becomes thinner. Moving down along the length of the rod, the stress decreases because the lower parts bear lesser weight of the rod. With reduced stress, the lateral strain also reduces. Hence, the diameter of the rod gradually increases from top to bottom. 

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पाठ 14: Some Mechanical Properties of Matter - MCQ [पृष्ठ २९८]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 14 Some Mechanical Properties of Matter
MCQ | Q 6 | पृष्ठ २९८

संबंधित प्रश्‍न

Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0 ×106 Pa.


A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Figure. The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively. At what point along the rod should a mass be suspended in order to produce (a) equal stresses and (b) equal strains in both steel and aluminium wires.

 


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The ratio stress/strain remain constant for small deformation of a metal wire. When the deformation is made larger, will this ratio increase or decrease?


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A load of 10 kg is suspended by a metal wire 3 m long and having a cross-sectional area 4 mm2. Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is 2.0 × 1011 N m−2

 

Answer in one sentence.

Define strain.


A spiral spring is stretched by a weight. The strain will be: 


A rod of length l and negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths (Figure). The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively.

(YAl = 70 × 109 Nm−2 and Ysteel = 200 × 109 Nm–2)

  1. Mass m should be suspended close to wire A to have equal stresses in both the wires.
  2. Mass m should be suspended close to B to have equal stresses in both the wires.
  3. Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.
  4. Mass m should be suspended close to wire A to have equal strain in both wires.

Is stress a vector quantity?


A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g = 3.1πms-2, what will be the tensile stress that would be developed in the wire?


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(take g = 10 ms-2)


What is the physical quantity defined as the internal restoring force per unit area of a body?


The SI unit of stress is:


What are the dimensions of strain?


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