Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
We know that,
P=VI= I1R
Given, P = 1200 watt , I= 5A
R = `"P"/"I"^2 = 1200/(5 xx 5) = 48 Omega`
and, V = `"P"/"I" = 1200/5` = 240 V
APPEARS IN
संबंधित प्रश्न
The values of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below:
| I (amperes) | 0.5 | 1.0 | 2.0 | 3.0 | 4.0 |
| V (volts) | 1.6 | 3.4 | 6.7 | 10.2 | 13.2 |
Plot a graph between V and I and calculate the resistance of that resistor.
What is the unit of electric charge?
The p.d. across a lamp is 12 V. How many joules of electrical energy are changed into heat and light when: a current of 2 A flows through it for 10 s?
If the potential difference between the ends of a fixed resistor is halved, the electric power will become:
Write an expression for the electrical power spent in flow of current through a conductor in terms of current and resistance.
A V-I graph for a nichrome wire is given below. What do you infer from this graph? Draw a labelled circuit diagram to obtain such a graph.
Explain why potential difference is always less than the e.m.f. of a cell?
Suppose there are three resistors A, B, and C having resistances r1, r2, and r3 respectively. If R represents their equivalent resistance, establish the following relation `1/"R" = 1/"r"_1 + 1/"r"_2 + 1/"r"_3`, when joined in parallel.
A current of 100 mA. flows through a wire. The charge on an electron is 1.6 × 10-19 C. Find the number of electrons passing per second through the cross-section of the conductor.
A cylindrical conductor of length l and uniform area of cross section A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section.
