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A Copper Wire of Diameter 1.6 Mm Carries a Current of 20 A. Find the Maximum Magnitude of the Magnetic Field → B Due to this Current. - Physics

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प्रश्न

A copper wire of diameter 1.6 mm carries a current of 20 A. Find the maximum magnitude of the magnetic field `vecB` due to this current.

संख्यात्मक
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उत्तर

Given:

Magnitude of current, I = 20 A

Diameter of the wire, d = 1.6 × 10−3 m

∴ Radius of the wire = 0.8 × 10−3 m

The magnetic field intensity is given by

\[B = \frac{\mu_0 I}{2\pi r}\]

\[= \frac{2 \times {10}^{- 7} \times 20}{0 . 8 \times {10}^{- 3}} = 5\] mT

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पाठ 13: Magnetic Field due to a Current - Exercises [पृष्ठ २५०]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 13 Magnetic Field due to a Current
Exercises | Q 3 | पृष्ठ २५०

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