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प्रश्न
A coin placed at the bottom of a beaker appears to be raised by 4.0 cm. If the refractive index of water is 4/3, find the depth of the water in the beaker.
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उत्तर
Let Real depth = x
∵ Refracture Index, μ = `"Real depth"/"Apparent depth"`
⇒ `4/3="x"/("x"-4)`
⇒ 4x − 16 = 3x
∴ x = 16 cm.
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संबंधित प्रश्न
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While tracing the path of a ray of light passing through a rectangular glass slab a student tabulated his observations as given below:
|
S.NO. |
∠i |
∠r |
∠e |
|
I |
60° |
40° |
61° |
|
II |
50° |
36° |
51° |
|
III |
40° |
28° |
39° |
|
IV |
30° |
20° |
31° |
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(B) II
(C) III
(D) IV
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