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प्रश्न
A coin placed at the bottom of a beaker appears to be raised by 4.0 cm. If the refractive index of water is 4/3, find the depth of the water in the beaker.
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उत्तर
Let Real depth = x
∵ Refracture Index, μ = `"Real depth"/"Apparent depth"`
⇒ `4/3="x"/("x"-4)`
⇒ 4x − 16 = 3x
∴ x = 16 cm.
संबंधित प्रश्न
Four students P, Q, R and S traced the path of a ray of light passing through a glass slab for an angle of incidence 40° and measured the angle of refraction. The values as measured them were 18°; 22°; 25° and 30° respectively. The student who has performed the experiment methodically is
(A) P
(B) Q
(C) R
(D) S
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