Advertisements
Advertisements
प्रश्न
A coin placed at the bottom of a beaker appears to be raised by 4.0 cm. If the refractive index of water is 4/3, find the depth of the water in the beaker.
Advertisements
उत्तर
Let Real depth = x
∵ Refracture Index, μ = `"Real depth"/"Apparent depth"`
⇒ `4/3="x"/("x"-4)`
⇒ 4x − 16 = 3x
∴ x = 16 cm.
APPEARS IN
संबंधित प्रश्न
Define refraction and state the laws of refraction.
A student traces the path of a ray of light through a rectangular glass slab for the different values of angle of incidence. He observes all possible precautions at each step of the experiment. At the end of the experiment, on analyzing the measurements, which of the following conclusions is he likely to draw?
(A) ∠i = ∠e < ∠r
(B) ∠i < ∠e < ∠r
(C) ∠i > ∠e > ∠r
(D) ∠i = ∠e > ∠r
The speed of light in glass is 2 × 105 km/s. What is the refractive index of glass?
How can you bend light away from the normal?
In fig 4.18, name the ray which represents the correct path of light while emerging out through a glass block.
Explain briefly what causes the twinkling of stars at night.
The figure shows two prisms A and B. A monochromatic ray of light PO is incident at the face of the prism A. Complete the diagram to show the path of the ray till it emerges out of the prism B.
Explain with the help of a diagram of how fish is able to see the objects above it.
Calculate the velocity of light in a glass block of refractive index 1.5. (Velocity of light in air = 3 × 108 m/s)
The speed of light in air is 3 × 108 ms-1. Calculate the speed of light in water. The refractive index of water is 4/3.
