मराठी

A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.

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प्रश्न

A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.

पर्याय

  • True

  • False

MCQ
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उत्तर

This statement is True.

Explanation:

First, we draw a circle and a point from the given information

Now, distance between origin i.e., O(0, 0) and P(5, 0),

OP = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

OP = `sqrt((5 - 0)^2 + (0 - 0)^2` 

= `sqrt(5^2 + 0^2)`

= 5

= Radius of circle and distance between origin O(0, 0) and Q(6, 8),

OQ = `sqrt((6 - 0)^2 + (8 - 0)^2`

= `sqrt(6^2 + 8^2)`

= `sqrt(36 + 64)`

= `sqrt(100)`

= 10

We know that, if the distance of any point from the centre is less than/equal to/more than the radius, then the point is inside/on/outside the circle, respectively.

Here, we see that, OQ > OP

Hence, it is true that point Q(6, 8), lies outside the circle.

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पाठ 7: Coordinate Geometry - Exercise 7.2 [पृष्ठ ८१]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 10
पाठ 7 Coordinate Geometry
Exercise 7.2 | Q 7 | पृष्ठ ८१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

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Case Study -2

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