Advertisements
Advertisements
प्रश्न
A chord is 12 cm away from the centre of the circle of radius 15 cm. Find the length of the chord
Advertisements
उत्तर
Radius of a circle (OA) = 15 cm
Distance from centre to the chord (OC) = 12 cm
In the right ΔOAC,
AC2 = OA2 – OC2
= 152 – 122
= 225 – 144
= 81
AC = `sqrt(81)`
= 9
Length of the chord (AB)
= AC + CB
= 9 + 9
= 18 cm.
APPEARS IN
संबंधित प्रश्न
Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at center.
The perimeter (in cm) of a square circumscribing a circle of radius a cm, is
In the given figure, if chords AB and CD of the circle intersect each other at right angles, then x + y =
In the given figure, BC is a tangent to the circle with centre O. OE bisects AP. Prove that ΔAEO ∼ Δ ABC.
Find the area of the shaded region in the figure If ABCD is a rectangle with sides 8 cm and 6 cm and O is the centre of the circle. (Take π= 3.14)
A, B, C are any points on the circle with centre O. If m(arc BC) = 110° and m(arc AB) = 125°, find measure arc AC.
C(O, r1) and C(O, r2) are two concentric circles with r1 > r2 AB is a chord of C(O, r1) touching C(O, r2) at C then ______
In the adjoining figure ‘O’ is the center of the circle, ∠CAO = 25° and ∠CBO = 35°. What is the value of ∠AOB?
In the following figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to ______.
From the figure, identify a sector.
