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A Bullet of Mass 20 G Enters into a Fixed Wooden Block with a Speed of 40 M S−1 and Stops in It. Find the Change in Internal Energy During the Process.

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प्रश्न

A bullet of mass 20 g enters into a fixed wooden block with a speed of 40 m s−1 and stops in it. Find the change in internal energy during the process.

बेरीज
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उत्तर

Given:-

Mass of bullet, m = 20g = 0.02 kg

Initial velocity of the bullet, u = 40 m/s

Final velocity of the bullet = 0 m/s

`"Initial kinetic energy of the bullet"=1/2m u^2=1/2xx0.02xx40xx40=16J`

Final kinetic energy of the bullet = 0

Change in energy of the bullet = 16 J

It is given that the bullet enters the block and stops inside it. The total change in its  kinetic energy is responsible for the change in the internal energy of the block.

∴ Change in internal energy of the block = Change in energy of the bullet = 16 J

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Thermal Expansion of Solids
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पाठ 25: Calorimetry - Exercises [पृष्ठ ४७]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 25 Calorimetry
Exercises | Q 10 | पृष्ठ ४७

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