Advertisements
Advertisements
प्रश्न
A boy pulls a box up to 10 m with a force of 5 kgf. Calculate the work done by him.
Advertisements
उत्तर
Given, force = 5kgf = 5 kgf x 10 ms-2= 50N
displacement = 10m
Work done = force x displacement = 50 x 10 = 500J
APPEARS IN
संबंधित प्रश्न
Write the expression for work done by a force.
A body, when acted upon by a force of 10 kgf, moves to a distance 0.5 m in the direction of force. Find the work done by the force. Take 1 kgf = 10 N.
Find the kinetic energy of a body of mass 1 kg moving with a uniform velocity of 10 m s-1.
Fill in the blank with suitable word :
1 joule is the work done when a force of 1 __________ moves an object through a distance of one __________ in the direction of __________.
Give two examples of couple action in our daily life.
A man lifts a mass of 10 kg from the floor to a shelf 4 meter high. If g = 10 ms-2, what is the work done?
Fill in the boxe to show the corresponding energy transformation.

Give an example
Chemical energy changes to heat energy.
State whether work is done or not, by writing yes or no, in the following case:
A boy climbs up 20 stairs.
