Advertisements
Advertisements
प्रश्न
A boy pulls a box up to 10 m with a force of 5 kgf. Calculate the work done by him.
Advertisements
उत्तर
Given, force = 5kgf = 5 kgf x 10 ms-2= 50N
displacement = 10m
Work done = force x displacement = 50 x 10 = 500J
APPEARS IN
संबंधित प्रश्न
A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughing the length of the field?
Why is a jack screw provided with a long arm?
Name a common device where a gear train is used
A force acts on a body and displaces it by a distance S in a direction at an angle θ with the direction of the force. What should be the value of θ to get the maximum positive work?
Is work a scalar or a vector quantity?
Write the formula for work done on a body when the body moves at an angle to the direction of force. Give the meaning of each symbol used.
What happens to the work done when the dispacement of body is at right angles to the direction of force acting on it? Explain your answer.
A force of 50 N acts on a body and moves it a distance of 4 m on horizontal surface. Calculate the work done if the direction of force is at an angle of 60° to the horizontal surface.
No work is done by a man moving on a horizontal road while carrying a box on his head. Explain.
What should be the characteristic of a source of energy?
