Advertisements
Advertisements
प्रश्न
An electric motor of power 100 W is used to drive the stirrer in a water bath. If 50% of the energy supplied to the motor is spent in stirring the water. Calculate the work done on the water in one minute.
Advertisements
उत्तर
An Electric motor :
Power (P) = 100 watt.
Time (t) = 1 minute = 60 seconds
∴ Work done by motor = Produced energy
= P × t
= 100 × 60
= 6000 Joule
∴ Work done on water by motor = 50% of total produced energy
`=50/100xx6000`
= 3000 Joule.
संबंधित प्रश्न
A machine raises a load of 750 N through a height of 16 m in 5 s. calculate:
- energy spent by machine,
- power at which the machine works.
State the energy transformation on the following:
Electricity is obtained from solar energy.
What is the work done against gravity when a body is moved horizontally along a frictionless surface?
What should be the angle between the direction of force and the direction of motion of a body so that the work done is zero?
In which of the following case the work done by a force will be maximum : when the angle between the direction of force and direction of motion is 0° or 90°?
What is the SI unit of work?
An object is dropped from a height H. when is its
(i) P.E. maximum,
(ii) K.E. maximum,
(iii) P.E. = K.E.?
A bucketful of water is to be drawn from a well ______ will be done when a ______ is applied to do this because there will be a ______ of water.
(displacement, work, force)
