Advertisements
Advertisements
प्रश्न
A body starts from rest and acquires a velocity 10 m s-1 in 2 s. Find the acceleration.
Advertisements
उत्तर
Here, final velocity = 10 m/s
Initial velocity = 0 m/s
Time taken = 2s
Acceleration = (Final Velocity - Initial Velocity)/time
= (10/2) ms-2
= 5 ms-2
APPEARS IN
संबंधित प्रश्न
Which of the two can be zero under certain conditions : average speed of a moving body or average velocity of a moving body ?
Fill in the following blank with suitable word :
A motorcycle has a steady……………. of 3 m/s2. This means that every………………. its…………….. increases by………….
Fill in the following blank with suitable word :
Velocity is the rate of change of……………………… It is measured in.............. .
What is meant by the term acceleration ? State the SI unit of acceleration.
A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.
Differentiate between uniform acceleration and variable acceleration.
A body, initially at rest, starts moving with a constant acceleration 2 m s-2. Calculate: (i) the velocity acquired and (ii) the distance travelled in 5 s.
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?

A stone thrown vertically upwards takes 3 s to attain maximum height. Calculate
- initial velocity of the stone
- maximum height attained by the stone. (Take g = 9.8 ms−2)
Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of `"u"_1^2 : "u"_2^2` (Assume upward acceleration is –g and downward acceleration to be +g)
