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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A 60 W load is connected to the secondary of a transformer whose primary draws line voltage. If a current of 0.54 A flows in the load, what is the current in the primary coil? Comment

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प्रश्न

A 60 W load is connected to the secondary of a transformer whose primary draws line voltage. If a current of 0.54 A flows in the load, what is the current in the primary coil? Comment on the type of transformer being used.

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उत्तर

PS = 60 W, IS = 0.54 A, IP = ?

PS = VSIS

60 = VS × 0.54

`60/0.54` = VS

VS = 111.10 Volt

In multiple of 11

VS = 110 Volt

Ratio factor of transformer 'r` = output voltage/input voltage

`r = V_S/V_P` ⇒ `r = (110  "Volt")/(220  "Volt") = 1/2`

Or r < 1, so transformer is step down transformer.

In transformer, output power = input power.

ISVS = IPVP

`I_P = (I_SV_S)/V_P = (0.54 xx 110)/220`

IP = 0.27 ampere

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पाठ 7: Alternating Current - MCQ I [पृष्ठ ४४]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
पाठ 7 Alternating Current
MCQ I | Q 7.24 | पृष्ठ ४४

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