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A 100 μF capacitor is charged with a 50 V source supply. Then source supply is removed and the capacitor is connected across an inductance, as a result of which 5A current flows through the inductanc

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प्रश्न

A 100 μF capacitor is charged with a 50 V source supply. Then source supply is removed and the capacitor is connected across an inductance, as a result of which 5A current flows through the inductance. Calculate the value of the inductance.

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उत्तर

Here, C = 100 μF = 100 × 10−6 F = 10−4 F

V = 50 volt, i = 5A, L = ?

The energy stored in the electric field in the capacitor = `1/2"CV"^2`

The energy stored in the magnetic field in the inductor = `1/2"Li"^2`

As energy stored in inductor = energy stored in capacitor,

∴ `1/2"CV"^2 = 1/2"Li"^2`

∴ L = `"C" "V"^2/"i"^2`

∴ L = C`("V"/"i")^2`

`= 10^-4(50/5)^2 = 10^-4 xx 10^2 = 10^-2  "H"`

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पाठ 13: AC Circuits - Exercises [पृष्ठ ३०५]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 13 AC Circuits
Exercises | Q 23. | पृष्ठ ३०५

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