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प्रश्न
A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s−1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.
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उत्तर
Length of the rod, l = 1 m
Angular frequency, ω = 400 rad/s
Magnetic field strength, B = 0.5 T
One end of the rod has zero linear velocity, while the other end has a linear velocity of lω.
Average linear velocity of the rod, `"v" = ("l"omega + 0)/2`
= `("l"omega)/2`
Emf developed between the centre and the ring,
e = Blv
= `"Bl"(("l"omega)/2)`
= `("Bl"^2omega)/2`
= `(0.5 xx (1)^2 xx 400)/2`
= 100 V
Hence, the emf developed between the centre and the ring is 100 V.
संबंधित प्रश्न
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The dimensions of self or mutual inductance are given as ______.
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The mutual inductance M12 of coil 1 with respect to coil 2 ______.
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The Henry, the SI unit of mutual inductance, is named after whom?
What is the effect of a larger cross-sectional area of the coils on mutual inductance?
What is the effect of winding coils on a soft iron core?
What does the coupling factor \[K\] quantify?
Why can \[B_2\] be assumed uniform across the entire area of the inner coil?
What is the mutual inductance of a small circular coil of radius \[r_1\] at the centre of a large circular coil of radius \[r_2\] when \[r_1\ll r_2\] ?
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