मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

22.22 Gram of Urea Was Dissolved in 300 Grams of Water. Calculate the Number of Moles of Urea and Molality of the Urea Solution. (Given: a Molar Mass of Urea = 60 Gram Mol-1) - Chemistry

Advertisements
Advertisements

प्रश्न

22.22 gram of urea was dissolved in 300 grams of water. Calculate the number of moles of urea and molality of the urea solution. (Given: a Molar mass of urea = 60 gram mol-1)

Advertisements

उत्तर

Moles of urea = `22.22/60`

= 0.370 moles

Molality (m) = `"Moles of urea"/"Mass of water" xx 1000` 

= `(0.370 xx 1000)/300`

= 1.23 moles  kg-1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2017-2018 (March)

APPEARS IN

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.


Calculate the molarity of the following solution: 

30 g of \[\ce{Co(NO3)2 * 6H2O}\] in 4.3 L of solution.


Define Molality.


Define Mass percentage.


A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.


If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.


Calculate the mass percentage of aspirin (C9H8O4) in acetonitrile (CH3CN) when 6.5 g of C9H8O4 is dissolved in 450 g of CH3CN.


Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution required for the above dose.


When KOH solution is added to potassium dichromate solution the colour of solution
changes to yellow, because _______

(A) chromate ion changes to dichromate ion

(B) dichromate ion changes to chromate ion

(C) oxidation number of chromium changes from + 6 to + 4

(D) oxidation number of chromium changes from + 4 to +6


The sum of all mole fraction for a mixture is always equal to ____________.


2.5 litres of NaCl solution contain 5 moles of the solute. What is the molarity?


The mole fraction of the solute in one molal aqueous solution is ____________.


What is the normality of a 1 M solution of H3PO4?


If N/10 50 ml H2SO4, N/3 30 ml HNO3, N/2 10 ml HCl is mixed and solution is made to 1 L. Then normality of the resultant solution is:


Which of the following units is useful in relating concentration of solution with its vapour pressure?


Mole fraction of C3H5(OH)3 in a solution of 36 g of water and 46 g of glycerine is ______.


Out of molality (m), molarity (M), formality (F) and mole fraction (x), those which are independent of temperature are:


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

V/V (volume percentage)


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

x (mole fraction)


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

m (Molality)


The concentration of water molecules in pure water at 298 K is?


3.36 M sulphuric acid solution is 29% H2SO4 calculate the density of the solution.


Calculated the mole fraction of benzene in a solution containing 30% by mass of its is carbon tetrachloride


138 g ethyl alcohol is mixed with 72 g of water. The ratio of mole fraction of alcohol to water is ______.


4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10−1. The value of x is ______. (Rounded-off to the nearest integer)


250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is ______ × 1021. (Nearest integer) (NA = 6.022 × 1023).


A given solution of H2O2 is 30 volumes. Its concentration in terms of molarity is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×