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Π ∫ 0 X Sin X Cos 4 X D X

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प्रश्न

\[\int\limits_0^\pi x \sin x \cos^4 x dx\]

बेरीज
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उत्तर

\[Let, I = \int_0^\pi x \sin x \cos^4 x d x ............(1)\]

\[ = \int_0^\pi \left( \pi - x \right) \sin\left( \pi - x \right) \cos^4 \left( \pi - x \right) d x \]

\[ = \int_0^\pi \left( \pi - x \right) \sin x \cos^4 x d x ..............(2)\]

Adding (1) and (2)

\[2I = \int_0^\pi \left[ x \sin x \cos^4 x + \left( \pi - x \right) \sin x \cos^4 x \right] d x \]

\[ = \int_0^\pi \left( x + \pi - x \right) \sin x \cos^4 x d x \]

\[ = \pi \int_0^\pi \sin x \cos^4 x d x \]

\[ = \pi \left[ \frac{- \cos^5 x}{5} \right]_0^\pi \]

\[ = \pi\left[ \frac{1}{5} + \frac{1}{5} \right]\]

\[ = \frac{2\pi}{5}\]

\[Hence, I = \frac{\pi}{5}\]

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पाठ 19: Definite Integrals - Revision Exercise [पृष्ठ १२२]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
Revision Exercise | Q 42 | पृष्ठ १२२

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